Let \(Y \to \Omega\) be the universal monomorphism. Then \(Y\) is the terminal object.
Proof
Write \(p\colon Y \to \Omega\) for the universal monomorphism, and let \(t\colon * \to \Omega\) be the map classifying the identity \(\id_*\colon * \to *\), exhibited by a pullback square of the form We claim \(s\) is an inverse to the canonical map \(q\colon Y \to *\), showing \(Y\) is terminal. Since \(q \circ s\) is homotopic to \(\id_*\), it remains to show that \(s \circ q\) is homotopic to \(\id_Y\).To this end, observe that we have two pullback diagrams of the following form: In particular, both bottom maps \(Y \to \Omega\) are classifying maps for \(\id_Y\), and it follows that \(p\) is homotopic to \(t \circ q\). We then get the chain of homotopies
\[p \circ (s \circ q) \simeq (p \circ s)\circ q \simeq t \circ q \simeq p \circ \id_Y,\]
so \(s \circ q\) defines an endomorphism of \(p\) in the slice category \(T_{/\Omega}\). Since \(p\) is a monomorphism, the anima of endomorphisms of \(p\) in \(T_{/\Omega}\) is \((-1)\)-truncated and nonempty (it contains \(\id_Y\)), hence contractible. Therefore \(s \circ q\) is homotopic to \(\id_Y\), as desired.